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Comparison of gtdiffrsp output with gtsrcmaps values

  • The diffuse response quantities are proportional, up to an energy-dependent factor (
    Unknown macro: {latex}

    $s(E)$

    ), to the probability densities of a given event for the corresponding source models. If
    Unknown macro: {latex}

    $\tilde

    Unknown macro: {S}

    (\hat

    Unknown macro: {p}

    )$

    is the spatial distribution of the diffuse component, then the diffuse response is
    Unknown macro: {latex}

    \newcommand

    Unknown macro: {phat}

    {{\hat

    Unknown macro: {p}

    }}
    \newcommand

    Unknown macro: {phatp}

    {{\hat

    ^\prime}}
    \newcommand

    Unknown macro: {E}

    \epsilon
    \newcommand

    Unknown macro: {Ep}

    \E^\prime
    \begin

    Unknown macro: {eqnarray}

    d_0(\Ep, \phatp) &= &\int d\phat \tilde

    Unknown macro: {S}

    (\phat) P(\phatp; \E, \phat, t) A(E, \phat, t) D(\Ep; \E, \phat, t)
    &= &\int d\phat \tilde

    (\phat) P(\phatp; \Ep, \phat, t) A(\Ep, \phat, t)
    \end

    Here, $\phat$ and $E$ are true photon direction and energy, $t$ is the arrival time, primes indicate measured quantities, $P$ is the PSF, $A$ is the effective area, and $D$ is the energy dispersion (taken to be a delta function in energy in the second line).

  • In gtsrcmaps the spatial distribution is multiplied by the exposure,
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    $E$

    and convolved with the mean PSF:
    Unknown macro: {latex}

    \newcommand

    Unknown macro: {phat}

    {{\hat

    Unknown macro: {p}

    }}
    \newcommand

    Unknown macro: {phatp}

    {{\hat

    ^\prime}}
    \newcommand

    Unknown macro: {E}

    \epsilon
    \newcommand

    Unknown macro: {Ep}

    \E^\prime
    \begin

    Unknown macro: {eqnarray}

    E(\Ep, \phat) &=& \int dt A(\Ep, \phat, t)
    P_

    Unknown macro: {rm avg}

    (\phatp; \Ep, \phat) &=& \frac

    Unknown macro: {1}
    Unknown macro: {E(Ep, phat)}

    \int dt A(\Ep, \phat, t) P(\phatp; \Ep, \phat, t)
    d_1(\Ep, \phatp) &=& \int_

    Unknown macro: {Deltaphatp}

    \int d\phat E(\Ep, \phat) P_

    (\phatp; \Ep, \phat) \tilde

    Unknown macro: {S}

    (\phat)
    \end

    $E$ is the time-integrated exposure and $P_

    Unknown macro: {rm avg}

    $ is the average PSF. The integral over $\phatp$ is over the pixel size ($\Delta\phatp$). For an inertial pointing, $E$ is just the effective area times the livetime $\Delta t$ and we should have
    \begin

    Unknown macro: {equation}

    d_0 = \frac

    Unknown macro: {d_1}
    Unknown macro: {Delta t Delta phatp}

    \end

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