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On Analog boards

DesignVer

PCB

#

LDOSupply/NetTP#SheetItem(s)ToState(1)Current draw[mA]Problem
Note(s)

Small

C00

LT3086EFEASIC_V2_5A = ASIC_ANA_PWR8R255→R253-->R256AGNDLoaded: 1kOhm-->390-->1kOhm1.05 + 0Minimum Load Current = 1mA. The LT3086 requires a minimum load current to ensure proper regulation and stability.
..........................................................................Note(s)
5R192DET_GND → R364 (0Ohm) → AGNDNO LOAD!
QuadC00
LT3086EFEA0+2_5V


See no sense load to AGND
0Possibly... no minimum load resistanceSee Small




A0+2_5V (sheet 18: ASIC_APWR)
18R255DET_GND → R364 (0Ohm) → AGNDNO LOAD!
QuadC01VR3 & VR4LT3086EFEVOUT (A0+2_5V)
9
See no sense load to AGND
Possibly... no minimum load resistanceSee Small



See Small







R10 & R11 (330 Ohm)


I_MON = I_OUT/1000 resistor for VR3 & VR4 → I_OUT = 1000*I_MON = (1000/330)*V_MON




ASIC_ANA_EN
7R1ASIC_ANA_EN → R1 (10kOhm) → AGNDLDO physically off at bootup





A0+2_5V137








A0+2_5V (sheet
22
19: ASIC_APWR)
22

19R264DET_GND → R364 (0Ohm) → AGNDNO LOAD!0Possibly... no minimum load resistance




A1+2_5V











A2+2_5V











A3+2_5V







QuadC01BVR14LT3086VOUT (D0+2_5V)
16












R36 (330 Ohm


I_MON = I_OUT/1000 resistor for VR3 & VR4 → I_OUT = 1000*I_MON = (1000/330)*V_MON




D0+2_5V117









D0+2_5V (sheet 19: ASIC_DPWR)
19

NO LOAD!0

(1) Without asic load added

On Digital boards

Testing Mods