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On Analog boards

DesignVerLDOSupplySheetItem(s)ToState(1)Current draw[mA]ProblemNote(s)

Small

C00

LT3086EFEASIC_V2_5A = ASIC_ANA_PWR8R255→R253-->R256AGNDLoaded: 1kOhm-->390-->1kOhm1.05 + 0
Minimum Load Current = 1mA. The LT3086 requires a minimum load current to ensure proper regulation and stability.




5R192DET_GND → R364 (0Ohm) → AGNDNO LOAD!QuadC00LT3086EFEA0+2_5VSee no sense load to AGND0Possibly... no minimum load resistanceSee SmallA0+2_5V (sheet 18: ASIC_APWR)18R255DET_GND → R364 (0Ohm) → AGNDNO LOAD!QuadC01LT3086EFEA0+2_5VSee no sense load to AGNDPossibly... no minimum load resistanceSee SmallA0+2_5V (sheet 22: ASIC_APWR)22R264DET_GND → R364 (0Ohm) → AGNDNO LOAD!0

(1) Without asic load added