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The blanket is constructed of mulitple layers of material:
Kevlar C21H15N3O3 6 layers on the top, 8 layers on the sides
Nextel Al2O3 (62.5%) SiO2 (24.5%) B2O3 (13%) 4 layers
Solomide Foam density = 0.005 g/cm3 Nor chemical formula is provided, we'll assume CH 4 layers, although this is not spelled out in the text but is derived from the numbers in section 7
MLI&Handling Layers density = 1.4 g/cm3 From the description sounds like mostly Kapton (C22H10N2O5) The only other material explicitly mentioned is Germanium, but after consulting with Dave Thompson (GSFC) it was decided that could be ignored..it only contributes 1000 Angstroms, or 0.00001 cm.
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The thickness of the top can be computed as:
MLI&Handling Layers: 0.07 cm
Solomide Foam: 4(0.65 cm)
Nextel: 4(0.043 cm)
Kevlar: 6(0.03 cm)
Total: 3.02 cm
From Section 7: Top ( 6 layers Kevlar): 0.137 + 0.119 + 0.015 + 0.098 = 0.36 g/cm2
Top 0.36 g/cm2 x 34350 cm2 = 12366 g
Top ignoring crown 0.36 g/cm2 x 32328 cm = 11638.08 g
Density: 0.36 g/cm2 / 3.02 cm = 0.12 g/cm3
Adjusted Density if we retain the 3.27 cm volume rather than shrinking to 3.02 cm: 0.13 g/cm3
Solomide Foam: 32328 cm2 (2.6 cm) (0.0055 g/cm3) = 420.26 g
CH 1 mole = 12.011 + 1.0079 = 13.089 g
420.26 g / 13.089 g = 32.11 moles
12.011 (32.11) = 385.65 g C
1.0079 (32.11) = 32.35 g H
Nextel: 32328 cm2 (4(0.043)) (0.69) = 3836.69 g
Al2O3 (62.5%) SiO2 (24.5%) B2O3 (13%)
32328 ( 0.625) = 2397.93 g
2(26.98154) + 3 (15.9994) = 101.96 g/mole
2397.93 / 101.96 = 23.52 moles
2(26.98154)(23.52) = 1269.21 g Al
3(15.9994)(23.52 = 1128.54 g O
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B2O3: 32328(0.13) = 498.77 g
B2O3: 2(10.81) + 3(15.9994) = 69.62 g/mole
498.77/69.62 = 7.164 moles
2(10.81)(7.164) = 154.89 g B
3(15.9994)(7.164) = 343.86 g O
Kevlar 32328 cm2 (6 (0.03 cm) ) (0.76 g/cm3) = 4422.47 g
C21H15N3O3 1 mole = 21(12.011) + 15 (1.0079) + 3 (14.0067) + 3 (15.9994) = 357.37 g
4422.47 g / 357.37 g = 12.38 moles
21(12.011)(12.38) = 3122.62 g C
15(1.0079)(12.38) = 187.17 g H
3(14.0067)(12.38) = 520.21 g N
3(15.9994)(12.38) = 594.22 g O
Kapton 32328 cm2 (0.07 cm) (1.4 g/cm3) = 3168.14 g
C22H10N2O5 1 mole = 22(12.011) + 10(1.0079) + 2(14.0067) + 5(15.9994) = 382.33 g
3168.14 / 382.33 = 8.29 moles
22(12.011)(8.29) = 2190.57 g C
10(1.0079)(8.29) = 83.55 g H
2(14.0067)(8.29) = 232.23 g N
5(15.9994)(8.29) = 663.18 g O