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Kevlar 32328 cm2 (6 (0.03 cm) ) (0.76 g/cm3) = 4422.47 g
C21H15N3O3 1 mole = 21(12.011) + 15 (1.0079) + 3 (14.0067) + 3 (15.9994) = 357.37 g
4422.47 g / 357.37 g = 12.38 moles
21(12.011)(12.38) = 3122.62 g C
15(1.0079)(12.38) = 187.17 g H
3(14.0067)(12.38) = 520.21 g N
3(15.9994)(12.38) = 594.22 g O
Kapton 32328 cm2 (0.07 cm) (1.4 g/cm3) = 3168.14 g