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Kevlar 16506 cm2 (8 (0.03 cm) ) (0.76 g/cm3) = 3010.69 g
C21H15N3O3 1 mole = 21(12.011) + 15 (1.0079) + 3 (14.0067) + 3 (15.9994) = 357.37 g
3010.69 g / 357.37 g = 8.42 moles
21(12.011)(8.42) =2123.79 g C
15(1.0079)(8.42) = 127.30 g H
3(14.0067)(8.42) = 353.81 g N
3(15.9994)(8.42) = 404.14 g O
Kapton 16506 cm2 (0.07 cm) (1.4 g/cm3) = 1617.59 g
C22H10N2O5 1 mole = 22(12.011) + 10(1.0079) + 2(14.0067) + 5(15.9994) = 382.33 g
1617.59/ 382.33 = 4.23 moles
22(12.011)(4.23) = 1117.74 g C
10(1.0079)(4.23) = 42.63 g H
2(14.0067)(4.232) = 118.50 g N
5(15.9994)(4.23) = 338.39 g O
Total for each element