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NADBlanketSideY_l

1756.34 mm

length in long (error) (X) dimension of Y-sides of blanket

NADBlanketSideX_l

1690.94 mm

length in long (Y) dimension of X-sides of blanket, shorter than Y-sides because Y-sides cover corners

NADBlanketSideZ

1075.11 mm

height of a side piece of the blanket: approx. height of ACD side tiles + height of cal

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Solomide Foam:  32328 cm2 (2.6 cm) (0.0055 g/cm3) = 420.26 g     
C22H10N2O5  1 mole = 22(12.011) + 10(1.0079) + 2(14.0067) + 5(15.9994) = 142.94 g
420.26 g / 142.94 g = 2.94 moles
22(12.011)(2.94) = 70.62 C
10(1.0079)(2.94) = 31.72 H
2(14.0067)(2.94) = 82.36 N
5(15.9994)(2.94) = 235.19 OCH 1 mole = 12.011 + 1.0079 = 13.089 g
420.26 g / 13.089 g = 32.11 moles
12.011 (32.11) = 385.65 g   C
1.0079 (32.11) = 32.35 g     H

Nextel:  32328 cm2 (4(0.043)) (0.69) = 3836.69 g
Al2O3 (62.5%) SiO2 (24.5%) B2O3 (13%)
32328 ( 0.625) = 2397.93 g
2(26.98154) + 3 (15.9994) = 101.96  g/mole
2397.93 / 101.96 = 23.52 moles
2(26.98154)(23.52) = 1269.21 g Al
3(15.9994)(23.52 = 1128.54 g    O

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Density:  0.41 g/cm2 / 3.08 cm =0.13 g/cm3

Solomide Foam (modeled as Kapton):  16506 cm2 (2.6 cm) (0.0055 g/cm3) = 236.04 g     
C22H10N2O5  1 mole = 22(12.011) + 10(1.0079) + 2(14.0067) + 5(15.9994) = 142.94 g
  236.04g / 142.94 g = 1.65 moles
22(12.011)(1.65) = 436.00 C
10(1.0079)(1.65) =  16.63 H
2(14.0067)(1.65) =  46.22 N
5(15.9994)(1.65) =  132.00 O

Nextel:  16506 cm2 (4(0.043)) (0.69) = 1958.93 g
Al2O3 (62.5%) SiO2 (24.5%) B2O3 (13%)
  16506( 0.625) =  g
2(26.98154) + 3 (15.9994) = 101.96  g/mole
2397.93 / 101.96 = 23.52 moles
2(26.98154)(23.52) = 1269.21 g Al
3(15.9994)(23.52 = 1128.54 g    O

SiO2:  32328(0.245) = 939.99 g
SiO2:    28.0855 + 2(15.9994) = 60.08 g/mole
939.99/60.08 = 15.65 moles
28.0855(15.65) = 439.53 g     Si
2(15.9994)(15.65) = 500.78 g O

B2O3: 32328(0.13) = 498.77 g
B2O3:   2(10.81) + 3(15.9994) = 69.62 g/mole
498.77/69.62 = 7.164 moles
2(10.81)(7.164) = 154.89 g     B
3(15.9994)(7.164) = 343.86 g O

Kevlar 16506 cm2 (8 (0.03 cm) ) (0.76 g/cm3) = 3010.69 g
C21H15N3O3  1 mole = 21(12.011) + 15 (1.0079) + 3 (14.0067) + 3 (15.9994) = 357.37 g
 3010.69 g / 357.37 g = 8.42 moles
21(12.011)(8.42) =2123.79 g   C
15(1.0079)(8.42) = 127.30 g     H
3(14.0067)(8.42) = 353.81 g     N
3(15.9994)(8.42) = 404.14 g     O

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